javascript - 將 TypeScript 枚舉轉換為物件陣列
我有一個這樣定義的枚舉:
export enum GoalProgressMeasurements {
Percentage = 1,
Numeric_Target = 2,
Completed_Tasks = 3,
Average_Milestone_Progress = 4,
Not_Measured = 5
}
然而,我希望它能以我們 API 的物件陣列/列表形式表示,如下所示:
[{id: 1, name: 'Percentage'},
{id: 2, name: 'Numeric Target'},
{id: 3, name: 'Completed Tasks'},
{id: 4, name: 'Average Milestone Progress'},
{id: 5, name: 'Not Measured'}]
有沒有一個簡單且符合原生語法的方法來做到這件事,或者我必須建立一個函數,將列舉型別轉換成整數和字串,然後把物件建立成陣列?
答案#1
如果你正在使用 ES8
僅在這種情況下,它將運作得非常好。它會給你所提供的 enum 的值陣列。
enum Colors {
WHITE = 0,
BLACK = 1,
BLUE = 3
}
const colorValueArray = Object.values(Colors); //[ 'WHITE', 'BLACK', 'BLUE', 0, 1, 3 ]
你將會得到像這樣的 colorValueArray:[ 'WHITE', 'BLACK', 'BLUE', 0, 1, 3 ]。所有的鍵會在陣列的前半部分,而所有的值會在後半部分。
甚至這種枚舉也能正常運作
enum Operation {
READ,
WRITE,
EXECUTE
}
但這個解決方案對像這樣的異質枚舉不起作用
enum BooleanLikeHeterogeneousEnum {
No = 0,
Yes = "YES",
}
答案#2
一個棘手的部分是 TypeScript 會在生成的物件中對枚舉進行「雙重」映射,因此它可以通過鍵和值來訪問。
enum MyEnum {
Part1 = 0,
Part2 = 1
}
將被發出為
{
Part1: 0,
Part2: 1,
0: 'Part1',
1: 'Part2'
}
所以你應該先過濾物件再進行映射。所以 @Diullei 的解法是正確的答案。這是我的實作:
// Helper
const StringIsNumber = value => isNaN(Number(value)) === false;
// Turn enum into array
function ToArray(enumme) {
return Object.keys(enumme)
.filter(StringIsNumber)
.map(key => enumme[key]);
}
像這樣使用它:
export enum GoalProgressMeasurements {
Percentage,
Numeric_Target,
Completed_Tasks,
Average_Milestone_Progress,
Not_Measured
}
console.log(ToArray(GoalProgressMeasurements));
答案#3
簡單來說,這將返回一個枚舉值的陣列:
Object.values(myEnum);
答案#4
列舉是存在於運行時的真實物件。因此,你可以通過如下方式反向映射:
let value = GoalProgressMeasurements.Not_Measured;
console.log(GoalProgressMeasurements[value]);
// => Not_Measured
根據這個,你可以使用以下程式碼:
export enum GoalProgressMeasurements {
Percentage = 1,
Numeric_Target = 2,
Completed_Tasks = 3,
Average_Milestone_Progress = 4,
Not_Measured = 5
}
let map: {id: number; name: string}[] = [];
for(var n in GoalProgressMeasurements) {
if (typeof GoalProgressMeasurements[n] === 'number') {
map.push({id: <any>GoalProgressMeasurements[n], name: n});
}
}
console.log(map);
參考資料: https://www.typescriptlang.org/docs/handbook/enums.html
答案#5
簡單解決方案。您可以使用以下函數將您的 Enum 轉換為物件陣列。
buildGoalProgressMeasurementsArray(): Object[] {
return Object.keys(GoalProgressMeasurements)
.map(key => ({ id: GoalProgressMeasurements[key], name: key }))
}
如果你需要去掉那個底線,我們可以使用正則表達式如下:
buildGoalProgressMeasurementsArray(): Object[] {
return Object.keys(GoalProgressMeasurements)
.map(key => ({ id: GoalProgressMeasurements[key], name: key.replace(/_/g, ' ') }))
}
答案#6
我使用
Object.entries(GoalProgressMeasurement).filter(e => !isNaN(e[0]as any)).map(e => ({ name: e[1], id: e[0] }));
一行簡單的程式碼就能完成工作。
它通過三個簡單的步驟完成工作
- 使用 Object.entries 載入鍵和值的組合。
- 過濾掉非數字(因為 TypeScript 會生成反向查找的值)。
- 然後我們將其映射到我們喜歡的陣列對象。
答案#7
多虧了 polkovnikov.ph,我終於能找到一個適用於大多數使用情境的解決方案。
該問題的有效解答
type Descripted<T> = {
[K in keyof T]: {
readonly id: T[K];
readonly description: string;
}
}[keyof T]
/**
* Helper to produce an array of enum descriptors.
* @param enumeration Enumeration object.
* @param separatorRegex Regex that would catch the separator in your enum key.
*/
export function enumToDescriptedArray<T>(enumeration: T, separatorRegex: RegExp = /_/g): Descripted<T>[] {
return (Object.keys(enumeration) as Array<keyof T>)
.filter(key => isNaN(Number(key)))
.filter(key => typeof enumeration[key] === "number" || typeof enumeration[key] === "string")
.map(key => ({
id: enumeration[key],
description: String(key).replace(separatorRegex, ' '),
}));
}
範例:
export enum GoalProgressMeasurements {
Percentage = 1,
Numeric_Target = 2,
Completed_Tasks = 3,
Average_Milestone_Progress = 4,
Not_Measured = 5
}
console.log(enumToDescriptedArray(GoalProgressMeasurements))
// Produces:
/*
[
{id: 1, description: "Percentage"},
{id: 2, description: "Numeric Target"},
{id: 3, description: "Completed Tasks"},
{id: 4, description: "Average Milestone Progress"},
{id: 5, description: "Not Measured"}
]
*/
另外,我有一個有用的工具函數,用來將列舉對象映射到它所擁有的可用值數組:
繪圖者
type NonFunctional<T> = T extends Function ? never : T;
/**
* Helper to produce an array of enum values.
* @param enumeration Enumeration object.
*/
export function enumToArray<T>(enumeration: T): NonFunctional<T[keyof T]>[] {
return Object.keys(enumeration)
.filter(key => isNaN(Number(key)))
.map(key => enumeration[key])
.filter(val => typeof val === "number" || typeof val === "string");
}
實際應用案例
- 數字列舉
enum Colors1 {
WHITE = 0,
BLACK = 1
}
console.log(Object.values(Colors1)); // ['WHITE', 'BLACK', 0, 1]
console.log(enumToArray(Colors1)); // [0, 1]
- 字串列舉
enum Colors2 {
WHITE = "white",
BLACK = "black"
}
console.log(Object.values(Colors2)); // ['white', 'black']
console.log(enumToArray(Colors2)); // ['white', 'black']
- 異質列舉
enum Colors4 {
WHITE = "white",
BLACK = 0
}
console.log(Object.values(Colors4)); // ["BLACK", "white", 0]
console.log(enumToArray(Colors4)); // ["white", 0]
- 列舉與具有導出函數的命名空間合併
enum Colors3 {
WHITE = "white",
BLACK = "black"
}
namespace Colors3 {
export function fun() {}
}
console.log(Object.values(Colors3)); // ['white', 'black', Function]
console.log(enumToArray(Colors3)); // ['white', 'black']
答案#8
class EnumHelpers {
static getNamesAndValues<T extends number>(e: any) {
return EnumHelpers.getNames(e).map(n => ({ name: n, value: e[n] as T }));
}
static getNames(e: any) {
return EnumHelpers.getObjValues(e).filter(v => typeof v === 'string') as string[];
}
static getValues<T extends number>(e: any) {
return EnumHelpers.getObjValues(e).filter(v => typeof v === 'number') as T[];
}
static getSelectList<T extends number, U>(e: any, stringConverter: (arg: U) => string) {
const selectList = new Map<T, string>();
this.getValues(e).forEach(val => selectList.set(val as T, stringConverter(val as unknown as U)));
return selectList;
}
static getSelectListAsArray<T extends number, U>(e: any, stringConverter: (arg: U) => string) {
return Array.from(this.getSelectList(e, stringConverter), value => ({ value: value[0] as T, presentation: value[1] }));
}
private static getObjValues(e: any): (number | string)[] {
return Object.keys(e).map(k => e[k]);
}
}
答案#9
在陣列中取得列舉值的範例:
export enum DocumentationTypeEnum {
GDPR = 'GDPR',
HELP = 'HELP',
OTHER = 'OTHER',
FOOTER = 'FOOTER'
}
const keys = Object.keys(DocumentationTypeEnum);
console.log(keys); // Output : ["GDPR", "HELP", "OTHER", "FOOTER"]
答案#10
我不喜歡上述任何答案,因為它們都無法正確處理 TypeScript 列舉中可以作為值的字串/數字混合情況。
以下函數遵循 TypeScript 列舉的語義,提供一個正確的鍵對值映射。由此,獲取對象數組、僅鍵或僅值都是簡單的。
/**
* Converts the given enum to a map of the keys to the values.
* @param enumeration The enum to convert to a map.
*/
function enumToMap(enumeration: any): Map<string, string | number> {
const map = new Map<string, string | number>();
for (let key in enumeration) {
//TypeScript does not allow enum keys to be numeric
if (!isNaN(Number(key))) continue;
const val = enumeration[key] as string | number;
//TypeScript does not allow enum value to be null or undefined
if (val !== undefined && val !== null)
map.set(key, val);
}
return map;
}
範例用法:
enum Dog {
Rover = 1,
Lassie = "Collie",
Fido = 3,
Cody = "Mutt",
}
let map = enumToMap(Dog); //Map of keys to values
let objs = Array.from(map.entries()).map(m => ({id: m[1], name: m[0]})); //Objects as asked for in OP
let entries = Array.from(map.entries()); //Array of each entry
let keys = Array.from(map.keys()); //An array of keys
let values = Array.from(map.values()); //An array of values
我也要指出,發帖者對枚舉的理解是顛倒的。枚舉中的「鍵」技術上是在左側,而值則在右側。TypeScript 允許你在右側重複值,無論你想重複多少次。
